The Acceleration Due to Gravity at 445 km Above Earth's Surface
About Acceleration Due to Gravity at Altitude of 445 km
A satellite is orbiting the Earth at an altitude of 445 km above the surface of the Earth. The question is, what is the acceleration due to gravity in m/s^2 at that altitude?
Final Answer
The acceleration due to gravity at an altitude of 445 km above the Earth's surface is approximately 8.54 m/s^2.
Explanation
To calculate the acceleration due to gravity at an altitude of 445 km above the surface of the Earth, we need to use the formula for gravitational acceleration:
g = G * (M/R^2)
Where:
g is the acceleration due to gravity
G is the gravitational constant (approximately 6.674 x 10^-11 N*m^2/kg^2)
M is the mass of the Earth (approximately 5.972 x 10^24 kg)
R is the distance from the center of the Earth to the satellite (radius of the Earth plus altitude)
Plugging in the values, we get:
g = (6.674 x 10^-11 N*m^2/kg^2) * (5.972 x 10^24 kg) / ((6,371 km + 445 km)^2)
Simplifying, we find that the acceleration due to gravity at that altitude is approximately 8.54 m/s^2.
What is the formula to calculate the acceleration due to gravity at a certain altitude above the Earth's surface? The formula to calculate the acceleration due to gravity at a certain altitude above the Earth's surface is: g = G * (M/R^2), where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the Earth, and R is the distance from the center of the Earth to the satellite.