How to Determine the Force in the X Direction at the Sheave?

What forces are acting on the shaft between the bearings?

Given the forces in the X direction at the left bearings, right bearing, and gear, what is the force in the X direction at the sheave?

Force Calculation

To determine the force in the X direction at the sheave, we need to analyze the forces acting on the shaft between the bearings. Given the forces at the left bearing (25 lbs), right bearing (30 lbs), and gear (-20 lbs), the force in the X direction at the sheave is 35 lbs.

The principle of equilibrium states that the sum of all forces acting on an object in equilibrium must be zero. In this case, we can consider the shaft between the bearings as the object in equilibrium.

Let's denote the force at the sheave as F_s. According to the principle of equilibrium, the sum of forces in the X direction must be zero. Therefore, we can write the equation:

Net force = 25 lbs + 30 lbs + (-20 lbs) = 55 lbs - 20 lbs = 35 lbs

From this equation, we can conclude that the force in the X direction at the sheave is 35 lbs. The positive sign indicates that the force acts in the same direction as the forces at the bearings and gear.

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