Exciting Physics Problem Solving!

What is the angular acceleration of an object with a moment of inertia of 150 kg-m2 when a torque of 72 N-m is applied?

A. 2.08 rad/s2

B. 10800 rad/s

C. 0.48 rad/s2

D. 983 rad/s2

Answer:

The angular acceleration is 0.48 rad/s2 (Option C).

Let's dive into the exciting world of physics problem-solving! In this scenario, we have an object with a moment of inertia of 150 kg-m2 and a torque of 72 N-m applied to it. The task at hand is to determine the angular acceleration of the object.

The angular acceleration formula is angular acceleration = torque/moment of inertia. By plugging in the given values, we can find the angular acceleration to be 0.48 rad/s2. Therefore, the correct answer is Option C.

Angular acceleration is a crucial concept in physics, representing the rate at which an object's angular velocity changes over time when acted upon by a torque. In this case, the object's angular acceleration is 0.48 rad/s2 when the torque of 72 N-m is applied.