Average Rate of Change Calculation in Chemical Reaction

What is the average rate of change of B in the given chemical reaction and time frame?

Determine the average rate of change of B in the reaction A ⟶ 2B from t=0 s to t=372 s with the following concentration data: time (s) - 0, 186, 372 and concentration (mol L^-1) - 0.640, 0.415, 0.190.

Answer:

The average rate of change of B from t=0 s to t=372 s is -0.45 mol L^-1 s^-1.

Explanation:

To calculate the average rate of change of B in the given chemical reaction over the specified time frame, we can use the formula:

Average rate = (change in concentration of B) / (change in time)

Using the provided data:

At t=0 s, concentration of B = 0.640 mol L^-1

At t=372 s, concentration of B = 0.190 mol L^-1

Substitute these values into the formula:

Average rate = (0.190 mol L^-1 - 0.640 mol L^-1) / (372 s - 0 s)

Calculating the above expression gives us an average rate of -0.45 mol L^-1 s^-1.

← Soar high with the power of mathematics Simplifying exponents in math made easy →