A kayaker's velocity calculation

A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.

What is the resultant velocity?

What is the resultant velocity? v = 2.91 m/s Explanation: Given that, A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west. We need to find the resultant velocity. Both velocities are perpendicular to each other. So, v=sqrt(v1^2+v2^2) =sqrt(2.5^2+1.5^2) =2.91 m/s So, the magnitude of the resultant velocity is equal to 2.91 m/s.
← Exciting speed calculation of a fighter jet Pitot static tube measurement of helium velocity →

More Posts: