A Car's Journey: Calculating Distance Traveled

A car having an initial speed of 16 meters per second is uniformly brought to rest in 4.0 seconds. How far does the car travel during this 4.0 second interval, let d is the distance covered by the car.

Calculation:

Given vi = 16, vf = 0, t = 4

By using the following formula we can calculate the acceleration;

vf - vi = at

a = (vf - vi) / t

a = (0 - 16) / 4

a = -4m/s²

Now use this formula to calculate distance

d = 1/2at² + vi*t

d = 1/2 (-4) (4)² + 16(4)

d = -32 + 64

d = 32 m

So, the car travels 32m during this 4-second interval.

Explanation:

The distance traveled by the car before stopping is 32 m.

What is the initial speed of the car in this scenario?

The initial speed of the car is 16 meters per second.

← How does boyle s law explain the expansion and contraction of air inside a plastic syringe Calculating torsional shear stress in a solid circular shaft →

More Posts: