A 3 Billiard Ball Collides with a Cue Ball

Explanation:

Given data:

• Mass of 3 billiard ball (m1) = 0.16 kg
• Initial velocity of the 3 billiard ball (U1) = 4.0 m/s
• Mass of the cue ball (m2) = 0.17 kg
• Initial velocity of the cue ball (U2) = 0 m/s

We are required to find the final velocities of both the cue ball and the 3 billiard ball after the collision.

Principle of conservation of linear momentum:

Total momenta before collision = total momenta after collision

M1U1 + M2U2 = (M1 + M2)V

Substitute the given values into the equation:

0.16*4.0 + 0.17*0 = (0.16 + 0.17)V

0.64 + 0 = 0.33V

V = 0.64/0.33 = 1.9394 m/s

Therefore, the final velocities of both the cue ball and 3 billiard ball after the collision are 1.9394 m/s.