Severity Index and Collision Distance Calculation

What is the severity index for the collision?

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How far does the person travel during the collision if the car was initially moving forward at 4.30 km/h?

Final answer:

The person travels a distance of approximately 0.1958 meters during the collision. The severity index cannot be calculated without the time (t) of the acceleration.

To calculate the severity index (SI) for the collision, we need to determine the acceleration in multiples of g and the time the acceleration lasts.

Given:

• Acceleration (a) = 35.0 m/s^2
• Initial velocity (u) = 4.30 km/h
• Final velocity (v) = 14.0 km/h

First, let's convert the initial and final velocities to m/s:

• Initial velocity (u) = 4.30 km/h = 1.19 m/s
• Final velocity (v) = 14.0 km/h = 3.89 m/s

Next, we can calculate the acceleration:

Using the equation v^2 = u^2 + 2as, we can solve for acceleration (a):

3.89^2 = 1.19^2 + 2a * s

15.12 = 1.4161 + 2a * s

2a * s = 13.7039

a * s = 6.85195

Since we know the acceleration (a) is 35.0 m/s^2, we can solve for s:

35.0 * s = 6.85195

s = 0.1958 m

Therefore, the person travels a distance of approximately 0.1958 meters during the collision.

To calculate the severity index (SI), we can use the formula SI = a^(5/2) * t:

SI = (35.0)^(5/2) * t

Since the time (t) is not given in the question, we cannot calculate the severity index without this information.