Converting from any base to base 10 in Java with `parseInt()`

How can we convert from any base to base 10 in Java?

Do you know how to use the `parseInt()` method in Java to convert from any base to base 10?

Converting from any base to base 10 in Java

Yes, you can convert from any base to base 10 in Java using the `parseInt()` method from the `Integer` class. This method allows you to specify the base of the number system you are converting from. Let's take a look at an example:

Imagine we have a binary number "101010" that we want to convert to base 10. We can achieve this conversion by using the following code:

String binaryString = "101010";

int base = 2;

int decimal = Integer.parseInt(binaryString, base);

System.out.println(decimal);

When we run this program, the output will be `42`, which is the decimal equivalent of the binary number `101010`.

To convert numbers in other bases to base 10, you can simply update the `base` variable accordingly. For instance, if you have a hexadecimal number "7F" that you want to convert to base 10, you can use the following code:

String hexString = "7F";

int base = 16;

int decimal = Integer.parseInt(hexString, base);

System.out.println(decimal);

When you run this code, the output will be `127`, which represents the decimal equivalent of the hexadecimal number `7F`.

Using the `parseInt()` method in Java makes it easy to convert numbers from any base to base 10!

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