What is the mass of an iceberg with a volume of 783 m3 and a density of ice equal to 0.917 g/cm3?
The mass of the iceberg can be calculated by multiplying the volume and density of ice. Let's break down the calculation step by step:
Step 1:
Given data:
Volume of the iceberg (V): 783 m³
Density of ice (ρ): 0.917 g/cm³
Step 2:
Convert "V" to cm³
We will use the relationship 1 m³ = 10⁶ cm³.
783 m³ × (10⁶ cm³/1 m³) = 7.83 × 10⁸ cm³
Step 3:
Calculate the mass (m) of the iceberg
We will use the expression ρ = m/V
m = ρ × V
m = 0.917 g/cm³ × 7.83 × 10⁸ cm³
m = 7.18 × 10⁸ g
Step 4:
Convert "m" to kg
We will use the relationship 1 kg = 10³ g.
7.18 × 10⁸ g × (1 kg/10³ g) = 7.18 × 10⁵ kg
Therefore, the mass of the iceberg is 7.18 × 10⁵ kg.