Exciting Calculation of Entropy Changes for Fusion and Vaporization of Argon
What are the molar heats of fusion and vaporization of argon?
The molar heats of fusion and vaporization of argon are 1.3 kJ/mol and 6.3 kJ/mol respectively.
What are the melting point and boiling point of argon?
The melting point of argon is -190°C and the boiling point is -186°C.
Can you calculate the entropy changes for the fusion and vaporization of argon?
Answer:
The entropy changes for the fusion and vaporization of argon are 15.634 J/mol K and 72.289 J/mol K respectively.
Argon is a fascinating element with unique properties, including its molar heats of fusion and vaporization. The molar heat of fusion of argon is 1.3 kJ/mol, which represents the amount of heat required to convert one mole of solid argon into liquid argon at its melting point.
On the other hand, the molar heat of vaporization of argon is 6.3 kJ/mol, indicating the energy needed to transform one mole of liquid argon into gaseous argon at its boiling point.
With the melting point of argon at -190°C and the boiling point at -186°C, we can calculate the entropy changes for the fusion and vaporization processes. The entropy change for the fusion of argon is 15.634 J/mol K, while the entropy change for vaporization is 72.289 J/mol K.
These entropy changes showcase the energy transformations and molecular-level changes that occur during the phase transitions of argon. Understanding these processes is crucial in studying the behavior of argon and its applications in various fields.