Combustion of Benzene: Fun Chemistry Calculation!

How many milliliters of oxygen are needed to burn 3.5 ml of C₆H₆ at CNTP?

A. 26.25mL O₂

Answer:

The correct answer is 26.25mL O₂.

Hello there! Let's have some fun with chemistry calculations today. In this case, we are given the combustion reaction of benzene which needs to be balanced before we can calculate the volume of oxygen needed.

The balanced chemical equation for the combustion of benzene is: C₆H₆ + ¹⁵/₂ O₂ → 6CO₂ + 3H₂O

After balancing the equation, we see that there is a molar relationship between benzene and oxygen of 1:¹⁵/₂. This means that for every 1 ml of benzene, we need ¹⁵/₂ ml of oxygen.

By using this relationship, we can calculate the volume of oxygen needed to burn 3.5 ml of benzene:

3.5 mL C₆H₆ * (15/2 mL O₂ / 1 mL C₆H₆) = 26.25mL O₂

So, the answer is 26.25mL of oxygen is needed to burn 3.5 ml of C₆H₆ at CNTP. Chemistry can be fun and exciting when we dive into calculations like these! Keep exploring and learning. Cheers!