Chemical Reaction: CaCO3 Decomposition

What happens when CaCO3 decomposes at 12000°C?

What will be the volume of CO2 gas formed?

Answer:

When CaCO3 decomposes at 12000°C, it forms CO2 gas and CaO. The volume of CO2 gas formed is 25 L.

Calcium carbonate (CaCO3) decomposes at 12000°C to form carbon dioxide (CO2) gas and calcium oxide (CaO). In this reaction, 25 liters of CO2 gas are collected at 12000°C.

Now, the question is, what will be the volume of this CO2 gas after it cools to 250°C?

To calculate the volume of the gas at 250°C, we need to use the ideal gas equation:

V1 / T1 = V2 / T2

Where V1 is the initial volume (25 L), T1 is the initial temperature (12000°C), V2 is the final volume (which we need to find), and T2 is the final temperature (250°C).

Substitute the values into the equation:

V2 = (V1 x T2) / T1

Calculate the volume of the gas at 250°C:

V2 = (25 x 523) / 12273

V2 = 1.06 L

Therefore, the volume of the CO2 gas after it cools to 250°C is 1.06 liters.