Calculating the Amount of Phosphoric Acid in mmol

How to calculate the amount of phosphoric acid (H3PO4) in millimoles present in a reaction?

Given the following data:

• Volume of phosphoric acid: 0.1 mL
• Density of phosphoric acid: 1.685 g/mL
• Molecular weight of phosphoric acid: 98 g/mol

Answer:

There are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.

To calculate the amount of phosphoric acid in millimoles (mmoles) present in the reaction, we can use the provided data - the volume of phosphoric acid, its density, and its molecular weight. Here's a step-by-step explanation:

Step 1: Calculate the mass of the phosphoric acid solution

Mass = Volume × Density

Mass = 0.1 mL × 1.685 g/mL

Mass ≈ 0.1685 grams

Step 2: Convert mass to moles using the molecular weight

Moles = Mass / Molecular Weight

Moles = 0.1685 g / 98 g/mol

Moles ≈ 0.001717 moles

Step 3: Convert moles to millimoles

Millimoles ≈ 0.001717 moles × 1000

Millimoles ≈ 1.717 millimoles

Therefore, there are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.